$\left(2x^3-y\right)^5$

$8\left(-11+2\right)-3\left(+12-6\right)$

$\frac{d}{dx}xe^y-10y+3x=0$

$\log_{10}\left(54\right)-\log_{10}\left(2\right)=2\log_{10}\left(x\right)-\log_{10}\left(\sqrt{x}\right)$

$\frac{x-3}{3}+\frac{2x-1}{6}$

$1,6x\:-\frac{2}{5}x$