$\left(2x^3-y\right)^5$
$8\left(-11+2\right)-3\left(+12-6\right)$
$\frac{d}{dx}xe^y-10y+3x=0$
$\log_{10}\left(54\right)-\log_{10}\left(2\right)=2\log_{10}\left(x\right)-\log_{10}\left(\sqrt{x}\right)$
$\frac{x-3}{3}+\frac{2x-1}{6}$
$1,6x\:-\frac{2}{5}x$
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