$\int\left(\frac{10x-5}{x}\right)dx$
$\left(\frac{a}{3}-3\right)^2$
$\frac{dy}{dx}=\frac{3y}{x}+1$
$\left(a^6+5b^4-b^2\right)\left(\frac{1}{a^65b^4b^2}\right)$
$\sqrt[2]{4}-5$
$\frac{2x^2-5x+2}{2x-1}$
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