$36x^2+24x+4$
$-\:45\:-\:\left(-140\right)$
$\left(3\right)^3-\left(1\right)^3$
$\int\:\frac{u^5-4u^3+10}{u^3}du$
$4x^2-16x-9$
$4\sin\left(x\right)-\sqrt{2}=\sqrt{2}$
$40\cdot0.08$
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