Exercise
$\left(a+b^3c-\frac{3}{5}ab\right)^2+\left(\frac{1}{4}ab-\frac{3}{2}\right)$
Step-by-step Solution
Learn how to solve special products problems step by step online. Expand the expression (a+b^3c-3/5ab)^2+1/4ab-3/2. Expand the trinomial using the formula \left(a+b+c\right)^2 = a^2 + b^2 + c^2 + 2ab + 2ac + 2bc. When multiplying two powers that have the same base (a), you can add the exponents. Multiply the fraction and term in 2\cdot \left(-\frac{3}{5}\right)a^2b. Multiply 2 times -3.
Expand the expression (a+b^3c-3/5ab)^2+1/4ab-3/2
Final answer to the exercise
$a^2+b^{6}c^2+a^2\left(\left(-\frac{3}{5}\right)b\right)^2+2ab^3c-\frac{6}{5}a^2b-\frac{6}{5}b^{4}ca+\frac{1}{4}ab-\frac{3}{2}$