limu→1(3u+4)(2u−2)3(u−1)3\lim_{u\to1}\frac{\left(3u+4\right)\left(2u-2\right)^3}{\left(u-1\right)^3}u→1lim(u−1)3(3u+4)(2u−2)3
4−x2⋅ (16−8x2+x4)30\frac{\sqrt{4-x^2\cdot\:\left(16-8x^2+x^4\right)}}{30}304−x2⋅(16−8x2+x4)
∫(x+2)x3dx\int\frac{\left(\sqrt{x}+2\right)}{\sqrt{x}}^3dx∫x(x+2)3dx
16m2n4−5n3\frac { 16 m ^ { 2 } n ^ { 4 } } { - 5 n ^ { 3 } }−5n316m2n4
∫−12(x2−1)−(x2−2x−5)dx\int_{-1}^2\left(x^2-1\right)-\left(x^2-2x-5\right)dx∫−12(x2−1)−(x2−2x−5)dx
x2+4=xx2+4=xx2+4=x
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