∫(1(x−4)ln(x−4))dx\int\left(\frac{1}{\left(x-4\right)ln\left(x-4\right)}\right)dx∫((x−4)ln(x−4)1)dx
7x2+19x+10=7x+57x^2+19x+10=7x+57x2+19x+10=7x+5
z4+10z2+24z^4+10z^2+24z4+10z2+24
−3(−99)-3\left(-99\right)−3(−99)
−18+(−13+9)+14−(17−20)-18+\left(-13+9\right)+14-\left(17-20\right)−18+(−13+9)+14−(17−20)
−x>5-x>5−x>5
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