$\lim_{x\to\infty}\left(\frac{e^{3x}-e^{-3x}}{ln\left(x+3\right)}\right)$
$\left(x+6\right)\left(x-7\right)$
$-30x^4+14x^3+4$
$\frac{dx}{dt\:}=\:1-t+x-tx$
$\left(-37\right)-\left(-17\right)$
$\tan x-\sec x$
$\sqrt[5]{1-1}+\left(1+4\right)^2$
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