$4+8\cdot3-\frac{100}{\left(-5\right)}^2$

$\lim_{x\to+\infty}\left(15x\:ln\left(x\right)\right)$

$80p^2+200p+125$

$\frac{8x^2-16x+6}{2x+1}$

$\lim_{x\to\infty}\left(x\left(x+1\right)+1\right)$

$\frac{\:1+\:tan^2\left(x\right)}{csc\:\left(x\right)}=sec^2x$