Exercise
$\left(x+4\right)^2+\left(x-3\right)^2=\left(x+5\right)^2$
Step-by-step Solution
Learn how to solve problems step by step online. Solve the quadratic equation (x+4)^2+(x-3)^2=(x+5)^2. A binomial squared (difference) is equal to the square of the first term, minus the double product of the first by the second, plus the square of the second term. In other words: (a-b)^2=a^2-2ab+b^2. Expand the expression \left(x+4\right)^2 using the square of a binomial: (a+b)^2=a^2+2ab+b^2. Add the values 16 and 9. Combining like terms x^{2} and x^2.
Solve the quadratic equation (x+4)^2+(x-3)^2=(x+5)^2
Final answer to the exercise
$x=0,\:x=8$