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Exercise

$\left(x+6\right)\left(x-2\right)\:-\:\left(x+4\right)\left(x+3\right)$

Step-by-step Solution

Learn how to solve special products problems step by step online. Expand the expression (x+6)(x-2)-(x+4)(x+3). Simplify the product -(x+4). Multiply the single term x-2 by each term of the polynomial \left(x+6\right). Multiply the single term x by each term of the polynomial \left(x-2\right). When multiplying two powers that have the same base (x), you can add the exponents.
Expand the expression (x+6)(x-2)-(x+4)(x+3)

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Final answer to the exercise

$-3x-24$

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Similar Questions Solved

$\left(x+2\right)\left(x+3\right)$

$\left(2+\sqrt{y}\right)\left(2-\sqrt{y}\right)$

$\left(6x-5\right)\left(2x+3\right)$

$4\left(4a+5\right)$

$\left(5x+2y\right)\left(5x-2y\right)$

$\left(2x+6\right)^2$

$\left(x-6\right)\left(x-5\right)$

Main Topic: Special Products

Special products is the multiplication of algebraic expressions that follow certain rules and patterns, so you can predict the result without necessarily doing the multiplication.

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