$\lim_{x\to\infty}\left(\frac{3x^2-3x+9}{x}\right)$
$\lim_{x\to0}\left(\frac{1+tanx}{1+senx}\right)^{\frac{1}{x}}$
$\left(sec\left(x\right)\right)\left(csc\left(x\right)\right)\:=\:2csc\:x$
$-\left(3c-8\right)-3c$
$3b+3a+2c^2+2c^2+c^2+c$
$\left(3x^3y^4-5xy\right)^2$
$\frac{dy}{dx}=\frac{2x}{7y^2}$
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