$x^2-4x^3$
$\left(a^3b^4c^5+7\right)\left(a^3b^4c^5-7\right)$
$\frac{d}{dx}\left(x^4+y^4\right)=82$
$4\sin^2\left(\frac{x}{2}\right)+8\cos\left(x\right)-7=0$
$\left|-5\cdot5+12\right|$
$\frac{8a^2b^5}{4b^3}$
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