Exercise
$\left(x^{a+1}+x^{2a-1}\right)^3$
Step-by-step Solution
Learn how to solve special products problems step by step online. Expand the expression (x^(a+1)+x^(2a-1))^3. The cube of a binomial (sum) is equal to the cube of the first term, plus three times the square of the first by the second, plus three times the first by the square of the second, plus the cube of the second term. In other words: (a+b)^3=a^3+3a^2b+3ab^2+b^3 = (x^{\left(a+1\right)})^3+3(x^{\left(a+1\right)})^2(x^{\left(2a-1\right)})+3(x^{\left(a+1\right)})(x^{\left(2a-1\right)})^2+(x^{\left(2a-1\right)})^3 =. When multiplying exponents with same base we can add the exponents. When multiplying exponents with same base we can add the exponents. Multiply the single term 3 by each term of the polynomial \left(a+1\right).
Expand the expression (x^(a+1)+x^(2a-1))^3
Final answer to the exercise
$x^{\left(3a+3\right)}+3x^{\left(4a+1\right)}+3x^{\left(5a-1\right)}+x^{\left(6a-3\right)}$