Exercise
$\left(x^1+y^{3t}\right)^3$
Step-by-step Solution
Learn how to solve special products problems step by step online. Expand the expression (x^1+y^(3t))^3. Any expression to the power of 1 is equal to that same expression. The cube of a binomial (sum) is equal to the cube of the first term, plus three times the square of the first by the second, plus three times the first by the square of the second, plus the cube of the second term. In other words: (a+b)^3=a^3+3a^2b+3ab^2+b^3 = (x)^3+3(x)^2(y^{3t})+3(x)(y^{3t})^2+(y^{3t})^3 =. Simplify \left(y^{3t}\right)^2 using the power of a power property: \left(a^m\right)^n=a^{m\cdot n}. In the expression, m equals 3t and n equals 2. Multiply 3 times 2.
Expand the expression (x^1+y^(3t))^3
Final answer to the exercise
$x^3+3x^2y^{3t}+3xy^{6t}+y^{9t}$