$\left(3x^3-9y\right)^2$
$\lim\:_{x\to\:\infty\:\:}\frac{ln\left(x+8\right)}{x^{\frac{1}{x}}}$
$\lim_{x\to-2}\ln\left(6x^2+2\right)$
$\frac{9}{25}\:x\:\frac{15}{27}$
$3xy^2-18xy+27x$
$\left(5\:tan\:x\:+7\right)\left(tan\:x-1\right)=0$
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