$\frac{d}{dx}2x^2-3x^2$
$y'=\frac{3x}{y+4}$
$y'-y=y^2e^x$
$\left(8+u\right)\left(8-u\right)$
$\left(\frac{3m}{-2n^2\cdot2m^2n^2}\right)$
$\left(7-5\right)4-6\left|3+2\left(4-1\right)\right|$
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