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Exercise

(x2+2y)2−(x2−2y)2\left(x^2+2y\right)^2-\left(x^2-2y\right)^2

Step-by-step Solution

1

Expand (x2−2y)2\left(x^2-2y\right)^2

(x2+2y)2−(x4−4x2y+(−2y)2)\left(x^2+2y\right)^2-\left(x^{4}-4x^2y+\left(-2y\right)^2\right)
2

Simplify the product −(x4−4x2y+(−2y)2)-(x^{4}-4x^2y+\left(-2y\right)^2)

(x2+2y)2−x4−(−4x2y+(−2y)2)\left(x^2+2y\right)^2-x^{4}-\left(-4x^2y+\left(-2y\right)^2\right)
3

Simplify the product −(−4x2y+(−2y)2)-(-4x^2y+\left(-2y\right)^2)

(x2+2y)2−x4+4x2y−(−2y)2\left(x^2+2y\right)^2-x^{4}+4x^2y-\left(-2y\right)^2

Final answer to the exercise

(x2+2y)2−x4+4x2y−(−2y)2\left(x^2+2y\right)^2-x^{4}+4x^2y-\left(-2y\right)^2

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x+b2x+\frac{b}{2}
(x2+2y)2−(x2−2y)2
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