Exercise
$\left(x^2-7x-3\right)\left(x^2+7x+3\right)$
Step-by-step Solution
Learn how to solve problems step by step online. Simplify the product of conjugate binomials (x^2-7x+-3)(x^2+7x+3). The sum of two terms multiplied by their difference is equal to the square of the first term minus the square of the second term. In other words: (a+b)(a-b)=a^2-b^2.. Simplify \left(x^2\right)^2 using the power of a power property: \left(a^m\right)^n=a^{m\cdot n}. In the expression, m equals 2 and n equals 2. Expand the expression \left(7x+3\right)^2 using the square of a binomial. Take the square of the first term: 7x.
Simplify the product of conjugate binomials (x^2-7x+-3)(x^2+7x+3)
Final answer to the exercise
$x^{4}-49x^{2}-42x-9$