$8x^5+4x^3$
$-\frac{1}{3}x+\frac{1}{2}<\frac{6}{5}x-6$
$\int18x\:sen\left(3x\right)\:dx$
$\int\frac{x^2+8}{x^3-4x}dx$
$x^2+4x+4=81$
$469\:\:-68$
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