Exercise
$\left(x-3\right)\left(6-3x-x^2\right)^2\left(3-x\right)^2$
Step-by-step Solution
Learn how to solve integrals of rational functions problems step by step online. Expand the expression (x-3)(6-3x-x^2)^2(3-x)^2. A binomial squared (difference) is equal to the square of the first term, minus the double product of the first by the second, plus the square of the second term. In other words: (a-b)^2=a^2-2ab+b^2. Multiplying polynomials x-3 and 9-6x+x^2. Multiplying polynomials 9 and x-3. Multiplying polynomials x-3 and -6x+x^2.
Expand the expression (x-3)(6-3x-x^2)^2(3-x)^2
Final answer to the exercise
$1944x+27\left(-3x\right)^2x-39x^{5}-972x^2-126x^{3}+207x^{4}-972-27\left(-3x\right)^2-9\left(-3x\right)^2x^2-3x^{6}+\left(-3x\right)^2x^{3}+x^{7}$