$\frac{dy}{dx}=6-3y$
$4x^3+2x-x^2+6x^2-x^3+7+3x-9$
$10.4+8.009+11.025+6.75$
$\frac{\left(x^3+2x+1\right)}{x^2+1}$
$\left(12mn^6+9p\right)\left(12mn^6-9p\right)$
$\lim_{x\to\infty}\left(\frac{x^2-1}{x^3+4x-3}\right)$
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