Exercise
$\left(x-3\right)^2-x^2-8x>0$
Step-by-step Solution
Learn how to solve special products problems step by step online. Solve the inequality (x-3)^2-x^2-8x>0. A binomial squared (difference) is equal to the square of the first term, minus the double product of the first by the second, plus the square of the second term. In other words: (a-b)^2=a^2-2ab+b^2. Cancel like terms x^2 and -x^2. Combining like terms -6x and -8x. Moving the term 9 to the other side of the inequation with opposite sign.
Solve the inequality (x-3)^2-x^2-8x>0
Final answer to the exercise
$x>\frac{9}{14}$