$\int sinx\cdot e^{\left(-cosx\right)}dx$
$\int\left(\frac{4+y}{y}\right)dx$
$10y^2-x=0$
$\left(\left(\left(2^2\right)^3\right)^4\right)^5.\:2^6^3$
$y'=\frac{x^2}{1+y^2}$
$x\cdot y^'-y=1$
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