$-8\cdot3+\left(-24\right)$
$\int_0^1\left(arctan\left(2x\right)\right)dx$
$\left(2+3\right)\left(-4\right)-\left(-4\right)$
$\frac{cos\left(6x\right)}{sin\left(6x\right)}=cot\left(6x\right)$
$1+2\tan^2\left(x\right)$
$2x+x^2=6x$
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