$$\left(-x-3y+5z\right)^2$$

$$\int tan^3\left(x\right)\cdot sec^{\frac{3}{2}}x\:dx$$

$$-\left(y-12\right)\left(y-7\right)$$

$$51,6-0,624$$

$$xy'=lnx$$

$$\left(4a^5b^3c\right)\left(8ab^5c^3\right)$$