$\int-10ydx$
$-8+5-\left(9+12-15\right)-24$
$\left(-31\right)+\left(-6\right)-\left(-18\right)$
$\frac{2}{9}x<7+x$
$\frac{1}{\cot\left(x\right)}=\sin\left(x\right)\sec\left(x\right)$
$x^2-9x-20=0$
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