$-5.\sqrt{6}+4.\sqrt{6}$
$x^2-x-20=0$
$\frac{4}{9}x^2+\frac{4}{12}xy+\frac{1}{16}y^2$
$x2\:+\:3x\:+\:c\:=\:\frac{7}{4}+c$
$\int\frac{2x}{\left(x^3-3x^2+2x\right)}dx$
$\:x^3\:-\:3x^2\:+\:2x-\:2\:entre\:x\:-\:1$
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