Learn how to solve operations with infinity problems step by step online. Find the limit of (2^n)/(2^2^n) as n approaches infinity. Simplify the fraction \frac{2^n}{2^{\left(2^n\right)}} by 2. Apply the power rule of limits: \displaystyle{\lim_{x\to a}f(x)^{g(x)} = \lim_{x\to a}f(x)^{\displaystyle\lim_{x\to a}g(x)}}. The limit of a constant is just the constant. The limit of a polynomial function (n- 2^n) when n tends to infinity is equal to the limit of it's highest degree term (the term that when i'ts evaluated at a high value, grows quickier to infinity), so it's solution is equivalent to calculating the limit of only the highest degree term.

Find the limit of (2^n)/(2^2^n) as n approaches infinity