$-1-x^2+4x+1-x^2$
$\left(2x+8\right)\left(2x-9\right)$
$9-3+6\:\left(-6\right)$
$\frac{k^2\:+\:3k\:+\:2}{k^2}\:=\:0$
$232\:-\:5$
$5x-7>4-3x$
$+224-\left(-359\right)$
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