$\int\frac{x}{\left(x^2+x-2\right)}dx$
$x^2-4x^2$
$\frac{\sec^2\theta}{\tan^2\theta}$
$\frac{dy}{dx}-3x=y$
$\frac{\left(4x^2+6\right)}{\left(x^3+3x\right)}$
$\frac{1}{4}x+7\le\frac{1}{3}x-2$
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