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- Solve using L'Hôpital's rule
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Simplify the fraction $\frac{\sqrt[3]{6x^2-x^3}+x}{2.1}$
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$\lim_{x\to\infty }\left(0.4762\left(\sqrt[3]{6x^2-x^3}+x\right)\right)$
Learn how to solve problems step by step online. Find the limit of ((6x^2-x^3)^(1/3)+x)/2.1 as x approaches infinity. Simplify the fraction \frac{\sqrt[3]{6x^2-x^3}+x}{2.1}. Factor the polynomial 6x^2-x^3 by it's greatest common factor (GCF): x^2. The power of a product is equal to the product of it's factors raised to the same power. Simplify \sqrt[3]{x^2} using the power of a power property: \left(a^m\right)^n=a^{m\cdot n}. In the expression, m equals 2 and n equals \frac{1}{3}.