Exercise
$\lim_{x\to\infty}\left(\frac{\sqrt[3]{x}-\sqrt[3]{x+1}}{\sqrt[4]{x+1}-\sqrt[4]{x}}\right)$
Step-by-step Solution
Learn how to solve integral calculus problems step by step online. Find the limit of (x^(1/3)-(x+1)^(1/3))/((x+1)^(1/4)-x^(1/4)) as x approaches infinity. As it's an indeterminate limit of type \frac{\infty}{\infty}, divide both numerator and denominator by the term of the denominator that tends more quickly to infinity (the term that, evaluated at a large value, approaches infinity faster). In this case, that term is . Rewrite the fraction, in such a way that both numerator and denominator are inside the exponent or radical. Separate the terms of both fractions. Evaluate the limit \lim_{x\to\infty }\left(\frac{\sqrt[4]{\frac{x}{\left(\sqrt[3]{x}-\sqrt[3]{x+1}\right)^{4}}+\frac{1}{\left(\sqrt[3]{x}-\sqrt[3]{x+1}\right)^{4}}}}{\sqrt[4]{\frac{x}{\left(\sqrt[4]{x+1}-\sqrt[4]{x}\right)^{4}}+\frac{1}{\left(\sqrt[4]{x+1}-\sqrt[4]{x}\right)^{4}}}}\right) by replacing all occurrences of x by \infty .
Find the limit of (x^(1/3)-(x+1)^(1/3))/((x+1)^(1/4)-x^(1/4)) as x approaches infinity
Final answer to the exercise
indeterminate