Find the limit of $\frac{-3x^3+2x}{4x+8}$ as $x$ approaches $\infty $

Step-by-step Solution

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Final answer to the problem

$- \infty $
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Step-by-step Solution

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  • Solve using L'Hôpital's rule
  • Solve without using l'Hôpital
  • Solve using limit properties
  • Solve using direct substitution
  • Solve the limit using factorization
  • Solve the limit using rationalization
  • Integrate by partial fractions
  • Product of Binomials with Common Term
  • FOIL Method
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1

Factor the polynomial $-3x^3+2x$ by it's greatest common factor (GCF): $x$

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$\lim_{x\to\infty }\left(\frac{x\left(-3x^2+2\right)}{4\left(x+2\right)}\right)$

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Learn how to solve problems step by step online. Find the limit of (-3x^3+2x)/(4x+8) as x approaches infinity. Factor the polynomial -3x^3+2x by it's greatest common factor (GCF): x. If we directly evaluate the limit \lim_{x\to\infty }\left(\frac{x\left(-3x^2+2\right)}{4\left(x+2\right)}\right) as x tends to \infty , we can see that it gives us an indeterminate form. We can solve this limit by applying L'Hôpital's rule, which consists of calculating the derivative of both the numerator and the denominator separately. After deriving both the numerator and denominator, and simplifying, the limit results in.

Final answer to the problem

$- \infty $

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Function Plot

Plotting: $\frac{-3x^3+2x}{4x+8}$

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7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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