$\frac{dy}{dx}=\left(3\right)\left(y+1\right)$
$\frac{dy}{dx}=2x^3y-4x^3$
$5-6\cdot5^2+1$
$\sqrt[5]{b^9}$
$\left(d-6\right)^{\left(4\right)}\left(d+2\right)\left(d^{\left(2\right)}+7\right)\left(d-4\right)y=0$
$2x-5\le4x$
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