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Exercise

$\lim_{x\to\infty}\left(\frac{2x}{2^{2^x}}\right)$

Step-by-step Solution

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Because polynomial functions ($2x$) grow asymptotically slower than exponential functions ($2^{\left(2^x\right)}$), we can say that the expression $\lim_{x\to\infty }\left(\frac{2x}{2^{\left(2^x\right)}}\right)$ tends to zero as $x$ goes to infinity

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Main Topic: Limits by Direct Substitution

Find limits of functions at a specific point by directly plugging the value into the function.

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