$x^4-y^2$
$5\:\cdot3x$
$\frac{x-1}{2x-4}+\frac{x+2}{3x}=1$
$x^8\cdot\frac{x^8}{1}\cdot\frac{1}{x^8}\cdot\frac{1}{x^{16}}$
$\cos\left(u\right)=\frac{5}{13}$
$\left(-5\right)x\left(-2\right)x\left(-3\right)x\left(2\right)$
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