Because polynomial functions ($x^8$) grow asymptotically slower than exponential functions ($e^{0.02x}$), we can say that the expression $\lim_{x\to\infty }\left(\frac{x^8}{e^{0.02x}}\right)$ tends to zero as $x$ goes to infinity
Try other ways to solve this exercise
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!