$\frac{dy}{dx}=y^2-9$
$\frac{dy}{dx}=y^2-4$
$\left(y^2+2xy\right)dx-x^2dy=0$
$\frac{dy}{dx}=y-y^2$
$\frac{dy}{dx}=y\left(y+2\right)$
$\frac{dy}{dx}=\left(1+e^{-x}\right)\left(y^2-1\right)$
The limit of a function f(x) when x tends to infinity is the value that the function takes as the value of x grows indefinitely.
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