$\lim_{x\to0}\left(\frac{x^3-27}{x^2-4x+3}\right)$
$y'=\pi ycot\left(2\pi x\right)$
$8a^2+12ab-2ba$
$\sqrt[10]{32^2}$
$\lim_{x\to\infty}\left(\frac{\left(x+1\right)}{\left(x-3\right)}\right)$
$\left(a^{x+1}-46^{x-2}\right)^2$
$2\:\left(-2\right)^2+3y$
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