$x2\left(4x\:4+6\right)\:$
$\frac{\tan^2\theta\csc^2\theta-1}{\tan^2\theta}$
$\lim_{x\to0}\left(x^{16x}\right)$
$3x^2\left(4x^4+2x-6\right)$
$y\left(4\right)=\left(8x\right)^{6x}$
$\left(3a\:-\:5c\:+\:8y\:\right)\:y\:\left(\:-4c\:+\:5y\right)$
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