$\int\frac{x^2+2x+1}{\left(x+1\right)^3}dx$

$81m^{10}-36a^6$

$\frac{dy}{dx}=3x^2-4x+7$

$\lim_{x\to0}\left(\frac{\sqrt{2x+3}-x}{x-3}\right)$

$\frac{dy}{dx}=\frac{\left(1+y^2\right)\left(x-2\right)}{\left(4x-x^2\right)^{\frac{1}{2}}}$

$\sqrt{\sec^2\left(x\right)+\csc^2\left(x\right)}=\tan\left(x\right)+\cot\left(x\right)$

$\frac{\left(4x^3\right)}{\left(x^4+1\right)^2}$