$\lim_{x\to0.9}\left(6x+1\right)^{\cot\left(x\right)}$
$+7-\left(-3\right)+2$
$sec^2x+3=tan^2x+4$
$\int\:\left(\frac{2x-18}{\sqrt{x\:}+3}\right)dx$
$\int\left(\frac{3x^2}{2+x^3}\right)dx$
$\lim_{x\to1}\left(4-4x\right)$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!