$\frac{x^2-3x-40}{x-8}$
$x\frac{dy}{dx}+3y=2x^5$
$\sqrt[2]{1.7}$
$\left(27a^3+8b^3\right)$
$\sin\left(3x\right)\cdot\sin\left(2x\right)$
$\left(x^2+1\right)\frac{dy}{dx}+xy=\left(1-2x\right)\left(\sqrt{x^2+1}\right)$
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