As it's an indeterminate limit of type $\frac{\infty}{\infty}$, divide both numerator and denominator by the term of the denominator that tends more quickly to infinity (the term that, evaluated at a large value, approaches infinity faster). In this case, that term is
Separate the terms of both fractions
Simplify the fraction
Simplify the fraction by $x$
Evaluate the limit $\lim_{x\to{- \infty }}\left(\frac{2+\frac{3}{x}}{1+\frac{6}{x^2}}\right)$ by replacing all occurrences of $x$ by $- \infty $
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