$$x\left(3x^2+4x-7\right)-2$$

$$\frac{dy}{dx}+2ycot2x\:=cos2x$$

$$\int\frac{x-2}{x\left(x^2-4x+5\right)^2}dx$$

$$4^5.4^3$$

$$\left(-8\right)-\left(-15\right)+\left(+3\right)-\left(+6\right)$$

$$y'=y^2$$

$$12x^2\:+\:20x\:+\:8\:-\:4x^2\:+\:12x\:+\:8$$