$12-3x\ge-6$
$\lim_{x\to\frac{2}{3}}\left(\frac{4-9x^2}{2-3x}\right)$
$\frac{\left(x-2\right)\left(x-3\right)}{6}-\frac{\left(x+1\right)^2}{5}=2-x$
$16x^{2-40x+25}$
$a^9\:-\:b^9$
$4x^3+10x^3$
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