Find the limit of $\frac{x^2+6x+9}{x^2+7x+12}$ as $x$ approaches $-3$

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The trinomial $x^2+6x+9$ is a perfect square trinomial, because it's discriminant is equal to zero

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$\Delta=b^2-4ac=6^2-4\left(1\right)\left(9\right) = 0$

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Learn how to solve limits by factoring problems step by step online. Find the limit of (x^2+6x+9)/(x^2+7x+12) as x approaches -3. The trinomial x^2+6x+9 is a perfect square trinomial, because it's discriminant is equal to zero. Using the perfect square trinomial formula. Factoring the perfect square trinomial. Factor the trinomial x^2+7x+12 finding two numbers that multiply to form 12 and added form 7.

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Function Plot

Plotting: $\frac{x^2+6x+9}{x^2+7x+12}$

Main Topic: Limits by Factoring

Limits that require factorization techniques to solve them.

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