$\lim_{x\to\infty}\left(3+\frac{1}{x}\right)^x$
$2-5t+8+5t-8$
$69=1x+2x$
$\left(2x-\:3x^2\right)^2$
$\lim_{x\to0}\left(\left(\frac{1}{x}\right)ln\left(sqrt\left(\frac{1+x}{1-x}\right)\right)\right)$
$\frac{9x}{4}+4=\frac{1}{8}by8$
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