$\lim_{x\to\infty}\left(\left(2x\right)\sin\left(\frac{1}{x}\right)\right)$

$\left|15-\left(10-3-8\right)-\left(-12\right)\right|+\left|-8+15-\left(-10-5\right)\right|$

$\left(2xy^3-4x^3y^2\right)dx+\left(3x^2y^2-2x^4y\right)dy=0$

$\frac{dy}{dx}=\sin\left(2t\right)+\cos h\left(2t\right)$

$1\cdot10^9$

$36x^2+9y^2-16z^2+72x-18y+64z-19=0$