$\int x^2\left(x^3-1\right)^7dx$
$16x^2-8xy+4x^2$
$\lim_{x\to\infty}\left(\frac{e^{x^2}}{3-x^3}\right)$
$5\left(x+1\right)+6\left(x+2\right)=7\left(x+3\right)$
$0x^2-2x^3$
$\left(-7\right)\cdot\left(+1\right)-\left(-5\right)+\left(-2\right)-\left(-3\right)\cdot\left(-2\right)$
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